分析

打开，得到py文件

import hashlib   
for i in range(32,127):
    for j in range(32,127):
        for k in range(32,127):
            m=hashlib.md5()
            m.update('TASC'+chr(i)+'O3RJMV'+chr(j)+'WDJKX'+chr(k)+'ZM')
            des=m.hexdigest()
            if 'e9032' in des and 'da' in des and '911513' in des:
                print des

诶 我看不懂 运行一下 报错 直接找ai

ai给了我答案

import hashlib

for i in range(32, 127):
    for j in range(32, 127):
        for k in range(32, 127):
            m = hashlib.md5()
            m.update('TASC'.encode() + chr(i).encode() + 'O3RJMV'.encode() + chr(j).encode() + 'WDJKX'.encode() + chr(k).encode() + 'ZM'.encode())
            des = m.hexdigest()
            if 'e9032' in des and 'da' in des and '911513' in des:
                print(des)

得出flag{e9032994dabac08080091151380478a2}

非常草率……